Skip to main content
2 answers
1
Asked 861 views

Is being a college athlete difficult with the workload?

I'm not exactly sure if I want to play sports along with a heavy workload, but I will consider it. #college #athlete

+25 Karma if successful
From: You
To: Friend
Subject: Career question for you

1

2 answers


0
Updated
Share a link to this answer
Share a link to this answer

Alfredo’s Answer

Hi Zoe,

That's a good question because it can definitely be difficult with the workload (both academic and physical). You can go to college and not be part of the competitive sports teams, but still get to play in the club teams your sport in school has. If that is too much of a commitment you can also play recreationally through intramurals or random pickup games.

Playing a sport competitively and going to college can definitely be challenging, but it will be very rewarding. The benefits of playing a sport competitively while being a student include improving on: time management, teamwork, and communication. These are all essential skills to have both on and off the field/court. Regardless of what college major or career path you end up deciding on, you should definitely give it a try.
0
0
Updated
Share a link to this answer
Share a link to this answer

Val’s Answer

I played college basketball at Stanford University. What prepared me best were the habits I established before I entered college. If you are managing your time well, communicating with teachers, pushing yourself academically and athletically - you should be fine.
Where I played was doubly tough. Stanford is a very rigorous academic environment and Stanford basketball was an elite program. If you have goals you want to accomplish, then managing workload is not a fear but yet another obstacle.
Was it tough? Yes. Was it worth it ? Yes. Being a student athlete is an experience I carry with me 20 years later. You develop skills, connections and memories that are not possible by just being a student.
I'd do it all again if I had the chance. It's life changing.
0